2x^2-2x+25=4x^2-20x+25

Solution for 2x^2-2x+25=4x^2-20x+25 equation:

2x^2-2x+25=4x^2-20x+25

We move all terms to the left:

2x^2-2x+25-(4x^2-20x+25)=0

We get rid of parentheses

2x^2-4x^2-2x+20x-25+25=0

We add all the numbers together, and all the variables

-2x^2+18x=0

a = -2; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-2)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-2}=\frac{-36}{-4}
=+9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-2}=\frac{0}{-4}
=0
$